Problem 6: Sum of squares or Square of sum !!!!

Q. Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.


Sol: 
I think problem is also one of the easiest problems here. 
The problem can be easily solved through basic knowledge of Arithmetic-Geometric Progression....


We know that sum of squares of numbers from 1 to n is n(n+1)(2n+1)/6 and sum of the numbers from 1 to n is n(n+1)/2.
So, the result can be formulated into an expression


Difference= (n(n+1)/2) ^ 2  - n(n+1)(2n+1)/6 = n(n+1)( 3(n^2) - n -2 ) / 12


Now all that remains is calculation.......  :D


Please post your comments...
Suggestion for better algorithms are always welcome.....